Question

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Answer 1

Answer:

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Answer 2

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Solution :

• Force applied to the Piston A = 4 kg

• Area of cross section of Piston A = 8 cm²

• Area of cross section of Piston B = 320 cm²

i) Calculation of pressure acting on Piston A :

$\sf \bigstar \: \: Pressure = \dfrac{Thrust}{Area}$

→ P = 4/8

→ P = 0.5 kgf/cm²

ii) Calculation of pressure on Piston B :

From Pascal's law

★ Pressure acting on Piston A = Pressure acting on the Piston B

→ P = 0.5 kgf/cm²

iii) Thrust on Piston B

$\sf \bigstar \: \: Thrust = Pressure \times Area$

→ Thrust = 4 × 320/8

→ Thrust = 4 × 40

→ Thrust = 160 kgf