Question

kindly solve it with explanation......
ans is +2.80kcal

best answer will be marked as brainliest.........​

Answer 1

Answer:

Explanation:

WHEN TO AN SOLUTION INDEFINITE AMOUNT OF SOLVENT IS ADDED IS CALLED HEAT OF SOLUTION

AND IF DEFINITE AMOUNT OF SOLVENT IS ADDED IS CALLED INTEGRAL HEAT OF SOLUTION

AND IF IT IS CHANGING FROM ONE HYDRATED FORM TO ANOTHER HYDRATED FORM IT IS CALLED HEAT OF DILUTION

AND IF DEFINITE AMOUNT OF AMOUNT OF SOLVENT IS ADDED AND SALT OF ITS NATURAL STATE IS FORMED IS CALLED HEAT OF HYDRATION

THE ENTHALPY OF HYDRATION

CUSO4(S) + H2O = CUSO4.5H2O

THE ENTHALPY OF SOLUTION

CUSO4(S) + H2O = CUSO4(AQ)

IT IS A TRICKY QUESTION

NORMALLY ENTHALPY OF SOLUTIONS ARE GIVEN

WHEN ENTHALPY OF SOLUTIONS ARE GIVEN

ENTHALPY OF SOLUTION OF CUSO4

ENTHALPY OF SOLUTION OF CUSO4.5H2O

ON SUBTRACTING 2 FROM 1

WE GET HEAT OF HYDRATION

SO

DEL HYDRATION = DEL SOLUTION OF CUSO4  - DEL SOLUTION OF CUSO4.5H2O

DEL SOLUTION OF CUSO4.5H2O = DEL SOLUTION OF CUSO4 - DEL HYDRATION

=-15.89+18.69

=2.8 k cal

heat of hydration is always negative

heat of solution  of  crystal making salts  is negative

heat of solution of non crystal making salts is positive

heat of solution  of already crystalled is positive

heat of solution of strong acids and bases is negative

heat of solution of ions is negative

and by this you can judge heat of solution of cuso4.7h2o is positive