Kindly solve the problem, please give full explanation
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x=50(alternate interior)
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Here is your solution,
Let the upper triangle be ABC and lower triangle be DBC
∠A = 100°
∠ABD = x°
∠BCD = 50°
AB = AC (given)
So, ∠ABC = ∠ACB
Let ∠ABC = ∠ACB = ∠1
In ΔABC,
∠A+∠B+∠C = 180°
100°+∠1+∠1 = 180°
2∠1 = 180-100
2∠1 = 80°
∠1 = 80/2
∠1 = 40°
∠ABC = 40°
In ΔDBC,
DB = DC (given)
∠DBC = ∠DCB
So, ∠DBC = 50°
∠x = ∠ABC+∠DBC
∠x = 40°+50°
∠x = 90°
Hope it helped and please mark my answer as brainliest.
Sorry for late answer.............
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