kindly solve this asap
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The ans is above.
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circuit is forming Wheatstone bridge so no current in CD,so can be remove from circuit.
Now, resistance in BE = 6
total resistance = 6/2 = 3 .
current = 15/3 = 5 .
now current in arm BE = 5/2 = 2.5
so potential difference = 0 as point C and E are at same potential.
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