Kindly solve this problem.... (Don't write incorrect answers)
The one who will give me the correct answer... I will mark him as brainliest....
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very easy u should have studies the circles theorem that angels is the same segment are equal and are half if the angle at the centre in opposite segment
now we are give angle BAD =75 using theorem
75×2 = 150 so angle BOD = 150
Step-by-step explanation:
Now given that BC = CD eqn@
so, BOC=COD=75 from eqn @
Now , triangle Now in triangle OBD
OB=OD radius so angle OBD=ODB eqn●
NOW angle sum property of triangle
OBD + ODB + BOD = 180
NOW from eqn ●
2OBD = 180-150
OBD=30/2
OBD= 15 ANS..
NOW ABCD IS cyclic quadrilateral so
sum of opposite side = 180
now BAD + BCD = 180
BCD = 180-75
BCD = 105..
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