Question

kindly solve this question

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Answer 1

Answer:

x = ab , y = ab

Step-by-step explanation:

Given equations,

$\sf \bf :\longmapsto \dfrac{bx}{a} + \dfrac{ay}{b} = a^2 + b^2$ .. - (i)

$\sf \bf :\longmapsto x + y = 2ab$ .. -(ii)

can be solved using elimination

Multiplying (ii) by $\dfrac{b}{a}$

$\sf \bf :\longmapsto\dfrac{bx}{a} + \dfrac{by}{a} = 2b^2$ ..-(iii)

Now subtracting (iii) - (i):

$\sf \bf :\longmapsto\dfrac{bx}{a} - \dfrac{bx}{a} + \dfrac{by}{a} - \dfrac{ay}{b} = 2b^2 - a^2 - b^2$

$\sf \bf :\longmapsto y\dfrac{b^2-a^2}{ab} = -a^2 + b^2$

$:\longmapsto \boxed{\sf \bf y = ab}$

Now puting y = ab in (ii)

$\sf \bf :\longmapsto x + ab = 2ab$

$:\longmapsto \boxed{\sf \bf x = ab}$

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Answer 2

Answer

• look at the pic

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