Question

kindly solve this question plss​

Answer 1

Answer:

Given AP||TR, so,

Angle TRQ = Angle PAQ

= 45°

Now in ∆ TQR, we have,

Angle QTR + Angle TRQ + Angle TQR = 180° (Angle sum property)

77°+45°+ Angle TQR = 180°

Angle TQR = 180°-(77+45)

Angle TQR = 180-122

Angle TQR = 58°

Answer 2

We know that AP || TR

⇒Angle QRT = 45° (Alternate interior angles)

Now in ∆QTR,

By angle sum property,

Angle QTR + Angle QRT + Angle TQR = 180°

⇒77° + 45° + Angle TQR = 180°

⇒ 122° + Angle TQR = 180°

⇒ Angle TQR = 180° - 122°

∴ Angle TQR = 58°