Kindly solve this question with complete explanation..
I am not able to get it!!
: (
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Answered by
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hope u understand it .....
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DivyanshiJ:
Thank you! But, could you explain why -b/a= -a-1?
it is formula and we put value of alpha and beta in formula
ohh! But in simple if we do -b/a, we should get -(-3)/2.. Isn't it?
no value of b and a is taken from eq. and alpha and beta are zeroes.
Answered by
1
Here is the solution :
If there is a Quadratic equation such as :
ax² + bx + c = 0, With roots as d, and e,
Then, We can establish a relation like this :
-b/a = d + e,
and,
c/a = d*e,
Now, The given Quadratic Equation is :
x² + (a+1)x + b,
Now the roots are : 2 and -3,
From the 1st Statement we can write this !
-(a+1)/1 = 2-3 = -1
=> -a -1 = -1
=> -a = 0,
=> a = 0,
From the 1st statement again,
b/1 = 2*-3
=> b = -6,
Therefore :
Value of a = 0, and,
Value of b = -6,
=> The correct option is [D]
Hope you understand, Have a great day !
Thanking you, Bunti 360 !!
If there is a Quadratic equation such as :
ax² + bx + c = 0, With roots as d, and e,
Then, We can establish a relation like this :
-b/a = d + e,
and,
c/a = d*e,
Now, The given Quadratic Equation is :
x² + (a+1)x + b,
Now the roots are : 2 and -3,
From the 1st Statement we can write this !
-(a+1)/1 = 2-3 = -1
=> -a -1 = -1
=> -a = 0,
=> a = 0,
From the 1st statement again,
b/1 = 2*-3
=> b = -6,
Therefore :
Value of a = 0, and,
Value of b = -6,
=> The correct option is [D]
Hope you understand, Have a great day !
Thanking you, Bunti 360 !!
Thank you so very much!!! I knew you will be able to explain!! : )
Thanks for the Brainliest answer ! :) !
Pleasure!! : )
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