Question

Kinectic energy of a body is increased by 44percent what is the percent increase in the momentum

Answer 1

Kinetic energy and momentum are related as
K = p²/(2m)

For an object of mass m
K ∝ p²
K₂/K₁ = (p₂/p₁)² ....(1)

Let’s say initial kinetic energy and momentum be 100% each
Then, equation (1) will become
144% / 100% = (p₂ / 100%)²
1.44 = (p₂ / 100%)²
p₂ = √1.44 × 100% = 120%

Increase in momentum = p₂ - p₁
= 120% - 100%
= 20%

∴ Momentum is increased by 20%