kinematics, to find value of 'a'
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when 2 vectors are perpendicualar then there dot product is 0
so we get on solving
a^2-2a-3=0
a(a+1)-3(a+1)=0
so a=-1 n 3
so we go for +ve and ans is 3
so we get on solving
a^2-2a-3=0
a(a+1)-3(a+1)=0
so a=-1 n 3
so we go for +ve and ans is 3
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