Question

Kinetic energy acquired by the electron in hydrogen atom if it absorbs light radiation of energy 1.08*10

Answer 1

Answer:

K.E. = 6.920\times 10^{-22}K.E.=6.920×10−22 joules.

Explanation:

Since we have E = 1.08\times 10^{-17}E=1.08×10−17 ...................(1)

we know that

E = \dfrac{hc}{\lambda}E=λhc ....................................(2)

h=6.626\times 10^{-34}h=6.626×10−34 and c = 3\times 10^{8}c=3×108

so from (1) and (2) we get,

\lambda = 18.40\times 10^{-9} mλ=18.40×10−9m ....................(3)

we know the de-brogile relation

\lambda = \dfrac{h}{mv}λ=mvh ..........................(4)

m = mass of electron

So,from (3) and (4) we get,

v = 39\times 10^{3} m/sv=39×103m/s

we know that the kinetic energy is given by

K.E = \dfrac{mv^{2} }{2}K.E=2mv2

After putting values we get,

K.E. = 6.920\times 10^{-22}K.E.=6.920×10−22 joules.