kinetic energy of a body increase by 20%. Calculate the percentage increase in momentum of the body?
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*m.v^2 = (mv)^2/(2m) = p^2/(2m) . So, KE varies as square of the momentum. On 20% increase of p, KE varies as (1.2p)^2 or 1.44p^2. Hence, increase in KE is 44%.
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