Physics, asked by SonKun1, 1 year ago

Kinetic energy of a body is 300 joules force on 25 newton is applied to stop it.calculate the distance travelled by the body before comes to rest? Please answer ASAP

Answers

Answered by abhi178
42
kinetic energy = work done by body
                  given, kinetic energy = 300 J
                            force act on body = 25 N
but we know,
work done by body = force act on body × distance travelled by body along force e.g., W = f.s [ where s is distance travelled by the body ]
                         
now, 
K.E = W
300J = 25N × s
s = 300/25 = 12 m
hence, distance travelled by body = 12m 

Answered by Bhartingghs
1

Answer:

12m

Explanation:

kinetic energy = work done by body

                 given, kinetic energy = 300 J

                           force act on body = 25 k

but we know,

work done by body = force act on body × distance travelled by body along force e.g., W = f.s [ where s is distance travelled by the body ]

                         

now,  

K.E = W

300J = 25N × s

s = 300/25 = 12 m

hence, distance travelled by body = 12m  

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