Kinetic energy of a body is 300 joules force on 25 newton is applied to stop it.calculate the distance travelled by the body before comes to rest? Please answer ASAP
Answers
Answered by
42
kinetic energy = work done by body
given, kinetic energy = 300 J
force act on body = 25 N
but we know,
work done by body = force act on body × distance travelled by body along force e.g., W = f.s [ where s is distance travelled by the body ]
now,
K.E = W
300J = 25N × s
s = 300/25 = 12 m
hence, distance travelled by body = 12m
given, kinetic energy = 300 J
force act on body = 25 N
but we know,
work done by body = force act on body × distance travelled by body along force e.g., W = f.s [ where s is distance travelled by the body ]
now,
K.E = W
300J = 25N × s
s = 300/25 = 12 m
hence, distance travelled by body = 12m
Answered by
1
Answer:
12m
Explanation:
kinetic energy = work done by body
given, kinetic energy = 300 J
force act on body = 25 k
but we know,
work done by body = force act on body × distance travelled by body along force e.g., W = f.s [ where s is distance travelled by the body ]
now,
K.E = W
300J = 25N × s
s = 300/25 = 12 m
hence, distance travelled by body = 12m
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