Kinetic energy of a charged particle decreases by 10 J as it moves from a point at potential 100 v to 200 v. The charge on the particle is:
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Given:
Decrease in kinetic energy (∆K) = 10 J
Potential of points between which charge particle moves:
To Find:
Charge on the particle (q)
Answer:
From conservation of energy:
Increase in potential energy = Decrease in kinetic energy
∆U = ∆K = 10 J
Electric potential difference is the work done by external force in moving a unit positive charge from one point to other.
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