Question

kinetic energy of a particle moving along a circle of radius r depends on distance as KE = cs²

Find the firce acting on the particle​

Answer 1

Answer:

Explanation:

KE = 1/2 mv² = cs²

V = (√2c/m)s

a (t) = dv/dt= √2c/m × ds/dt

= v √2c/m

F (t) = ma (t) = mv√2c/m

= [m√2c/m × s]√2c/m = 2cs

Totsl force F = √F² (t) + F² (c)

= √(2cs)² + (mv²/r)²

F = 2cs √1+s²/r²

Answer 2

Explanation:

Work done = F.s

K.E = (1/2)mv^2 = cs^2

v = √2 (c/m)s

a=dv/dt = √2 (c/m) ds/dt

= v√2 c/m

Force = d(K.E)/ds = 2cs

Fnet = √(2cs)^2 + (mv^2/r)^2

= 2cs√[(1 + s^2/r^2 )]