Question

Kinetic energy of a particle moving along the
circle is ax. If R is the radius of the circle.
The radial force on the particle is
(2)
2 ax²
1+x271/2
(1)
(c) 2ax
(d) 2 aR²
2​

Answer 1

Answer:

1/2 m v^2=ax

then 2ax/m=v^2

then F=(m×2ax/m)/R

So F=2ax/R