Kinetic energy of an electron in H-atom where its bohr atomic radius is 4.761 angstrom
Answers
Answered by
6
Answer:
hey mate here is ur ans
Explanation:
We know, Bhor's radius
r
n
=52.9n
2
Pm →(1)
As we are given,
r
n
=4.761
A
˙
→(2)
equating both the equations
4.761×10
−10
=52.9n
2
×10 −10
n
2 =9n=3
hope it helps u
Similar questions