Chemistry, asked by sonukumar8291, 7 months ago

Kinetic energy of an electron in H-atom where its bohr atomic radius is 4.761 angstrom

Answers

Answered by preet123456789
6

Answer:

hey mate here is ur ans

Explanation:

We know, Bhor's radius

r

n

=52.9n

2

Pm →(1)

As we are given,

r

n

=4.761

A

˙

→(2)

equating both the equations

4.761×10

−10

=52.9n

2

×10 −10

n

2 =9n=3

hope it helps u

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