Chemistry, asked by gurramvaishnavi555, 6 months ago

Kinetic energy of an electron in H-atom where its Bohr atomic radius is 4.761 Å is

Answers

Answered by arghyag884
0

We know, Bhor's radius

r  

n

​  

=52.9n  

2

 Pm   →(1)  

As we are given,

r  

n

​  

=4.761  

A

˙

        →(2)

equating both the equations

4.761×10  

−10

=52.9n  

2

×10  

−10

 

n  

2

=9

n=3

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