Kinetic energy of an electron in H-atom where its Bohr atomic radius is 4.761 Å is
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We know, Bhor's radius
r
n
=52.9n
2
Pm →(1)
As we are given,
r
n
=4.761
A
˙
→(2)
equating both the equations
4.761×10
−10
=52.9n
2
×10
−10
n
2
=9
n=3
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