Question

Kinetic energy of an electron in the second bohr orbit

Answer 1

Explanation:

according to Bohr's postulate. mvr=nh2π. squaring both side. m2v2r2=n2h22π2. 12mv2 =n2h28(π2)mr2. Placing r2=(16a∘)2 for n = 2.

Answer 2

Explanation:

it can be find by the formula :

K.E = -13.6 × z^ 2/ n^ 2.

In second orbit the energy is -3.4eV.

Thank you.