kinetic energy of an object of mass 2kg moving with a speed of 3m/s and the potential energy of an object of mass 500g at a height of 20m area respectively (acceleration due to gravity is 10m/s^2)
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Answers
Answered by
0
Explanation:
Answer:
5 π / 3 rad / sec²
Explanation:
Given :
ω = 500 rpm
ω in term of rad / sec
= > ω = 500 × 2 π / 60 rad / sec
= > ω = 50 π / 3 rad / sec
Time t = 10 sec
We have to find angular acceleration α :
We know :
α = ω / t
Putting value here we get :
= > α = ( 50 π / 3 ) / 10 rad /sec²
= > α = 5 π / 3 rad / sec²
Hence we get required answer!
Answered by
1
Answer:
K.E. = 9 J
P.E. = 100 J
Explanation:
Given :
Mass m = 2 kg
Velocity v = 3 m / sec
Now kinetic energy is given as :
= > K.E. = 1 / 2 m v²
= > K.E. = 1 / 2 × 2 × 3² J
= > K.E. = 9 J
Now :
Mass m' =500 g = 0.5 kg
Height h = 20 m
Acceleration due to gravity g = 10 m / sec²
We know potential energy is given as :
= > P.E. = m g h
= > P.E. = 0.5 × 10 × 20 J
= > P.E. = 100 J
Hence we get required answer!
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