kinetic energy of an object of mass 2kg moving with a speed of 3m/s and the potential energy of an object of mass 500g at a height of 20m are respectively (acceleration due to gravity is 10m/s^2)
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1
Explanation:
Answer:
5 π / 3 rad / sec²
Explanation:
Given :
ω = 500 rpm
ω in term of rad / sec
= > ω = 500 × 2 π / 60 rad / sec
= > ω = 50 π / 3 rad / sec
Time t = 10 sec
We have to find angular acceleration α :
We know :
α = ω / t
Putting value here we get :
= > α = ( 50 π / 3 ) / 10 rad /sec²
= > α = 5 π / 3 rad / sec²
Hence we get required answer!
Answered by
7
Answer:
K.E. 9J
P.E. =100J
Explanation:
Given
Mass m =2 kg
Velocity v=3 m/sec
Now kinetic energy is given as
>K.E. = 1/2 mv^2
=K.E. = 1/2 x 2 x 3 J
>K.E. = 1/2 mv
=>K.E. = 1/2 x2 x3^2J
=>K.E. =9J
Now:
Mass m'=-500 g = 0.5 kg
Height h = 20 m
Acceleration due to gravity g 10 m/sec?
We know potential energy is given as
=> P.E. =mgh
=>P.E. = 0.5 x 10x 20J
>P.E. 100 J
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