Kinetic energy of body decreases by 19%. Calculate percentage change in its linear momentum.
Answers
Answered by
40
K= p /2m
p= square root.2mK
Decrease in Kinetic energy= 19% of K
i.e 19/100 * K = 0.19 K
Final K.E , K'= 0.81
Final momentum, p' = square rt. 2mK' = sqr. rt. 2m x 0.81K
= 0.9 square root 2mK = 0.9p
increase in p
p-p'/p x 100 = p-0.9p/p x 100 = 10%
p= square root.2mK
Decrease in Kinetic energy= 19% of K
i.e 19/100 * K = 0.19 K
Final K.E , K'= 0.81
Final momentum, p' = square rt. 2mK' = sqr. rt. 2m x 0.81K
= 0.9 square root 2mK = 0.9p
increase in p
p-p'/p x 100 = p-0.9p/p x 100 = 10%
Attachments:
Answered by
28
percentage change in linear momentum is calculated as follows
Attachments:
Similar questions