Question

Kinetic energy per unit volume of h2 gas at ntp is

Answer 1

As kinetic energy is given by. 1/2*m*v²

so per unit volume it will be

K.e/V = (1/2*m*v²)/V where V is the volume

also m/V is density ,say, Q

therefore

KE/V = 1/2 * Q * v²

Answer 2

Answer:

Kinetic energy per unit volume of hydrogen gas at NTP is 163.21 J/L.

Explanation:

At NTP, 1 mole of gas occupies 22.4 L of volume.

So, n moles of hydrogen will have , V= n × 22.4 Liter volume

at NTP, temperature is taken as T = $20^oC = 293.15 K$

Kinetic energy of the 1 molecule of hydrogen gas.

$K.E=\frac{3RT}{2N_A}$

$1 mole = 6.022\times 10^{23} molecules$

$n moles = n\times 6.022\times 10^{23} molecules$

Kinetic energy of n moles of hydrogen gas:

$K.E'=\frac{3RT}{2N_A}\times n\times 6.022\times 10^{23}$

$=3,655.87\times n Joules$

Kinetic energy per unit volume of hydrogen gas at NTP is:

$\frac{K.E'}{V}=\frac{3,655.87\times n J}{22.4\times n L}=163.21 J/L$