Question

Kinetic theory of gases physics nootan numericals

Answer 1

Answer:

1+2+3+4+5+6+7+8+9

1×2×3×4×5×6×7×8×9

1÷2÷3÷4÷5÷6÷7÷8÷9=0

Answer 2

Answer:

Explanation:

Question-1.

Let A & B are two sample of ideal gases of equal mole .let T be the temperature of both the gas Let EA and EB are there total energy respectively .Let MA and MB are these respective molecular mass .which of these is true

a,EA > EB

b,EA < EB

c,EA =EB

d,none of these

Solution:1

EA = 3/2 nRT

EB = 3/2 nRT

;EA =EB

 

 

Question-2.

The velocities of the molecules are v, 2v, 3v, 4v & 5v. The rms speed will be

a,11v

b,v(11)1/2

c, v

d, 3.3v

Solution:2

Vrms= (∑ V2 / N)1/2

= [(V2 + 4V2 + 9V2 + 16V2 + 25V2)/5]1/2

=v(11)1/2

Question-3:

An ideal gas A is there.Initial temperature is 27°C.The temperature of the gas is increased to 927°C.Find the ratio of final Vrms to the initial Vrms

Solution-9:

Vrms=√3RT/M

So it is proportional to Temperature

Now

T1=27°C =300K

T2=927°C =1200K

So initial Vrms=k√300

Final Vrms=k√1200

ratio of final to initial=2:1