Question

Kiran has purchased an electric bulb rated as 100 W and 250 V. She connected the bulb with a battery of 250 V and put the switch on for 50 s. (a) What is the resistance of the filament of the bulb? (b) Find the current drawn from the battery. (c) Calculate the energy dissipated from the bulb in 50 s.
please answer this question

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Answer 1

Answer:

formulae need in this question are

p= I*i*r

p= v*v÷r

Step-by-step explanation:

so first find the resistance

as p= 100 and v= 250 GIVEN

so 100= 250*250÷r

r= 625ohm

for i = 100÷(250*250) = 0.0016 ampere

for energy dissipated use i*i*r*t Or power*time

100*50= 5000joule