Question

kirchoffs law examples​

Answer 1

Explanation:

Kirchhoff's Current Law Example No2

At point A, I1 is equal to IT, thus there will be an I1*R voltage drop across resistor R1. The circuit has 2 branches, 3 nodes (B, C and D) and 2 independent loops, thus the I*R voltage drops around the two loops will be: Loop ABC ⇒ 12 = 4I1 + 6I. Loop ABD ⇒ 12 = 4I1 + 12I.

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Answer 2

Kirchhoff's Current Law Example No2

At point A, I1 is equal to IT, thus there will be an I1*R voltage drop across resistor R1. The circuit has 2 branches, 3 nodes (B, C and D) and 2 independent loops, thus the I*R voltage drops around the two loops will be: Loop ABC ⇒ 12 = 4I1 + 6I. Loop ABD ⇒ 12 = 4I1 + 12I.