Question

Kishan digs a pit 8 m long, 6 m wide, and 2 m deep. The soil removed from the pit is
evenly spread over the area of his rectangular farm with dimensions 20 m by 12 m.
Calculate the rise in the level of the soil in his farm.

don't give silly questions and need answers with solution​

Answer 1

Answer:

The soil will rise by 0.4 m.

Step-by-step explanation:

Given:

• Length of the pit (l) = 8 m

• Breadth of the pit (b) = 6 m

• Height of the pit (h) = 2 m

• Length of the rectangular farm (l) = 20 m

• Breadth of the rectangle farm (b) = 12 m

To find:

Rise in the level of the soil of the farm (h)

Method to find:

First, we need to find the volume of soil in the pit.

Volume = l * b * h

⇒ Volume = 8 * 6 * 2 m³

⇒ Volume = 96 m³

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Secondly, we need to find the area of the rectangular farm.

Area = l * b

⇒ Area = 20 * 12

⇒ Area = 240 m²

_____________________________

To find the rise in the level of soil, we need to divide the volume of soil by the area of the field. (As (l*b*h / l*b) = h, i.e., rise in the level of soil)

⇒ 96 m³/240 m²

⇒ 0.4 m

______________________________

Hope it helps!

Answer 2

Answer:

0.4 is answer and solution is up