Question

Kishor owns a trapezium-shaped plot with the length of the parallel sides 12 m and 18 m. Find the area of this plot if the perpendicular between the parallel sides is 9 m​

Answer 1

go through the given attachment

Answer 2

$\mathfrak{ \pink{ \underline{ \blue{ \large{Correct \: Question: }}}}}$

Kishor owns a trapezium-shaped plot with the length of the parallel sides 12 m and 18 m. Find the area of this plot if the perpendicular between the parallel sides is 9 m.

$\mathfrak{ \pink{ \underline{ \blue{ \large{ Given:}}}}}$

• Parallel sides of trapezium = 12 m and 18 m
• Height of trapezium = 9 m

$\mathfrak{ \pink{ \underline{ \blue{ \large{To \: Find: }}}}}$

• Area of trapezium

$\mathfrak{ \pink{ \underline{ \blue{ \large{ Solution: }}}}}$

$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\ \mathfrak{ \underline{ \green{Formula \: to \: calculate \: the \: area \: of \: trapezium \: }}}$

$\boxed{ \boxed{ \star \: \: \: \: \: \:{ \large { \red{ \mathfrak{area = \frac{sum \: of \: parallel \: sides}{2} \times height}}}}}}$

According to question,

$\large{ \sf \longmapsto \: \: \: \: \: \: \: \:\: \: {area = \frac{12 +18}{2} \times 9}}$

$\large{ \sf \longmapsto \: \: \: \: \: \: \: \:\: \:area = \frac{30}{2} \times 9}$

$\large{ \sf \longmapsto \: \: \: \: \: \: \: \:\: \:area = 15\times 9}$

$\large{ \sf \longmapsto \: \: \: \: \: \: \: \:\: \: \boxed{ \boxed{ \purple{ \mathfrak{area = 135\: {m}^{2} }}}}}$

$\mathfrak{ \pink{ \underline{ \blue{ \large{ Hence:}}}}}$

The area of trapezium is 135 m²