kisi leep year me 53 Tuesday hone ki prayikata gyat kijiye
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in a leap year total number of days = 366
number of weeks = 366/7 = 52 weeks 2 days
the 2 days can be
(m ,t) ( t,w) ( w,th) ,( th,f ) ,( f,sat) ( sat,sun) ,( sun ,mon)
so favorable outcomes = ( m,t) ,( t,w)
probability = 2/7
number of weeks = 366/7 = 52 weeks 2 days
the 2 days can be
(m ,t) ( t,w) ( w,th) ,( th,f ) ,( f,sat) ( sat,sun) ,( sun ,mon)
so favorable outcomes = ( m,t) ,( t,w)
probability = 2/7
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leap year contains 366 days
=>52 weaks+2 days
52 weeks contains 52 Tuesdays
we will get 53 Tuesdays if one of the remaining two days is a Tuesday
total possibilities for two days are:
(sun,mon)(mon,tue)(tue,wed)(wed,thu)(thu,fri)(Fri,sat)(sat,sun)
there are 7 possibilities and out of these there are two favourable cases
therefore,P(53 tuesdays)=2/7
=>52 weaks+2 days
52 weeks contains 52 Tuesdays
we will get 53 Tuesdays if one of the remaining two days is a Tuesday
total possibilities for two days are:
(sun,mon)(mon,tue)(tue,wed)(wed,thu)(thu,fri)(Fri,sat)(sat,sun)
there are 7 possibilities and out of these there are two favourable cases
therefore,P(53 tuesdays)=2/7
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