Question

KISI MIKALAL ME DUM H TOH KRKE DIKHAO ????​

Answer 1

Answer:

Correct option is

A

5mA from B to A.

In the question, it is given that the charge of an electron is e=1.6×10

−19

C.

Therefore, the total charge flowing through the wire in 2 seconds will be given as 6.25×10

16

×1.6×10

−19

C=10×10

−3

C.

The rate of flow of charge is therefore

2 seconds

10×10

−3

C

=5×10

−3

C/s.

one C/s = one amp.

Hence, the current flowing through a conductor is 0.0005A, that is 5mA.

Answer 2

Answer:

One ampere is the current that flows through the lamp when one coulomb of charge passes in one second.