Math, asked by vaibhavikhalkar59, 10 months ago

kisme dum hai answer it....​

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Answered by PhysicsForever
1

Answer:

This is easy enough since all the data is already given.

Area of ∆SYK = 1/2* YK*SP

and, Area of ∆YTK = 1/2*TK*YT

So, ratio of these areas

= YK*SP/TK*YT

= 13*6/12*5 = 13/10

Hope this helps you !

Answered by rajnitiwari192003
0

Answer:

Area of triangle = 1/2 b h

Area of SYK : area of YTK

1/2 x 6 x 13: 1/2 x 12 x 5

6 x 13: 12x 5

13 : 2 x 5

13:10

Hope it is correct answer and it may help you......

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