Kisme kitan hai dum
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We given –5 is a root of the quadratic equation
2x²+px–15=0 ,
-5 satisfies the given equation.
2(-5)² + p(-5) - 15 = 0
50 - 5p - 15 = 0
35 - 5p = 0
5p = 35
p = 35/5
p = 7
Substituting p= 7 in (x²+x) + k = 0
we get, 7(x²+x)+ k = 0
7x² + 7x + k = 0
The roots of the equation are equal.
# Discriminant = b² - 4ac = 0
here, a = 7, b = 7, c = k
b² - 4ac = 0
(7)² - 4(7)(k) = 0
49 - 28k = 0
28k = 49
k = 49/28
k = 7/4
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