Question

km)
3. A body travels 200 cm in the first 2 s and
220 cm in the next 5 s. Calculate the
velocity at the end of the seventh second from
the start.
​

Answer 1

Answer:

ok

Explanation:

A body travels 200 cm in the first 2 seconds and 220 cm in the next four seconds. What will be its velocity at the end of the 7th second from the start? U+a=100 solving a=-15 m/s2 then u can solve for u =115 m/s. V=u+at=115+-15*7=10 cm/s

Answer 2

Answer:

s=ut+

2

1

at

2

For case 1.

200=2u+2a

u+a=100....(1)

For case 2. .i.e. next 4 seconds, we have distance =420 cm and time =6 s

420=6u+18a

u+3a=70....(2)

Solving equation 1 and 2, we get,

u=115 cm/s and a=−15 cm/s

2

Now by

v=u+at

v=115−15×7

v=10 cm/s

Explanation:

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