KmnO2+Hcl= kcl+Mncl2+H2O+O2 is equation ko sahi jamaye hit and trial method se
Answers
Answer:
To measure the quantity of MnCl2 dissolved in an aqueous solution, it was completely converted to KMnO4 using the reaction, MnCl2 + K2S2O8 + H2O → KMnO4 + H2SO4 + HCl (equation not balanced). Few drops of concentrated HCl were added to this solution and gently warmed.
Explanation:
To measure the quantity of MnCl2 dissolved in an aqueous solution, it was completely converted to KMnO4 using the reaction, MnCl2+K2S2O8+H2O→KMnO4+H2SO4+HCl (equation not balanced).
Few drops of concentrated HCl were added to this solution and gently warmed. Further, oxalic acid (225 g) was added in portions till the colour of the permanganate ion disappeared. The quantity of MnCl2 (in mg) present in the initial solution is:
(Atomic weights in g mol−1:Mn=55,Cl=35.5)