KMnO4 + H2SO4 gives K2SO4 + MnSO4 + H2O + (O) solve it with (POC) method
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Answer: the methods is the reduction of the agents
This is an oxidation-reduction (redox) reaction:
2 MnVII + 10 e- → 2 MnII (reduction)
5 SIV - 10 e- → 5 SVI (oxidation)
KMnO4 is an oxidizing agent, SO2 is a reducing agent.
Explanation:
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