Question

Kmno4+na2so3 gives mno2+na2so4+koh

Answer 1

Answer:

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Explanation:

Now use this information to balance the equation thinking of electron as money changing hands (can't disappear and can't appear, and so stays constant):

S(4+) – 2e = S(6+)

Mn(7+) + 3e = Mn(4+)

To assure equal given and taken electrons multiply first line to three and second to two (these are your initial coefficients, so keep their ration constant to assure equal number of given and taken electrons :

S(4+) – 2e = S(6+) X 3

Mn(7+) + 3e = Mn(4+) X 2

Put these initial coefficients into your equation and go through iteration steps:

2KMnO4 + 3Na2SO3 + H2O → MnO2 + Na2SO4 + KOH

2KMnO4 + 3Na2SO3 + H2O → 2MnO2 + 3Na2SO4 + KOH – equalize Mn and S

2KMnO4 + 3Na2SO3 + H2O → 2MnO2 + 3Na2SO4 + 2KOH equalize K, Na and H

2KMnO4 + 3Na2SO3 + H2O → 2MnO2 + 3Na2SO4 + 2KOH “oxygen check” 18 on the left and 18 on the right

Done!