kmno4 reacts with ki in basic medium to form i2and mno2. when 250 ml of 0.1M ki sol^n is mixed with 250ml of 0.02M kmno4 in basic medium, what is the no. of moles of i2 formed?
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Given 250 ml of 0.1M K I => 0.025 moles
and 250 ml of 0.02M of KMnO₄ => 0.005 moles
I am not sure of the reaction that takes place.... We need to find the products and then balance equation first.
2 K Mn O₄ + 6 K I => 2 Mn O₂ + 3 I₂ + 4 K₂ O
So n moles of Potassium Permanganate reacts with 3 n moles of potassium iodide to produce 1.5 n moles of Iodine gas.
So 0.005 moles of permanganate will react with 0.015 moles of Iodide, and produce 0.0075 moles of Iodine gas.
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If the reaction is
2 K MnO₄ + 6 K I + 4 H₂ O ==> 3 I₂ + 2 Mn O₂ + 6 K OH
then,
n moles of permanganate will react with 3 n moles of Iodide and produce 1.5 moles of Iodine.... Hence we will have 0.0075 moles of Iodine gas.
and 250 ml of 0.02M of KMnO₄ => 0.005 moles
I am not sure of the reaction that takes place.... We need to find the products and then balance equation first.
2 K Mn O₄ + 6 K I => 2 Mn O₂ + 3 I₂ + 4 K₂ O
So n moles of Potassium Permanganate reacts with 3 n moles of potassium iodide to produce 1.5 n moles of Iodine gas.
So 0.005 moles of permanganate will react with 0.015 moles of Iodide, and produce 0.0075 moles of Iodine gas.
================================
If the reaction is
2 K MnO₄ + 6 K I + 4 H₂ O ==> 3 I₂ + 2 Mn O₂ + 6 K OH
then,
n moles of permanganate will react with 3 n moles of Iodide and produce 1.5 moles of Iodine.... Hence we will have 0.0075 moles of Iodine gas.
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