KmNO4 reacts with oxalic acid as MnO4-+C2042- ------------>Mn2++CO2. Hence 50 ml of 0.04 M KMnO4 in acidic medium is chemically equivalent to?
OPTIONS:
100 ml 0.1 M oxalic acid
50 ml 0.1 M oxalic acid
50 ml 0.2 M oxalic acid
25 ml 0.1 M oxalic acid
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I think 50ml 0.1m oxalic acid is right
meghanamortha111:
can u give solution
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