Question

Ś kn/h 48
A daoin travels 360km with unifoam Spee
d. The speed of train is increased by
5km/ho, it takes G8 minutes less​

Answer 1

S= 48 kmph

Distance= 360 km

Therefore,

$tim \: taken = \frac{d}{s}$

$= \frac{360 \: km}{48 \frac{km}{h} }$

$= 7 \frac{1}{2} h$

Now, if the speed of train is increased by 5 kmph,

New speed = S1=48+5 kmph=53 kmph.

Decrease in time taken

$= \frac{d}{s } - \frac{d}{s1}$

$= ( \frac{15}{2} - \frac{360}{53} ) \: h$

$= \frac{759 - 720}{106} \: h$

$= \frac{39}{106} \: h$

$= \frac{39}{106} \times 60 \: min$

$= 22.1 \: minutes \: (approx.)$

HOPE IT HELPS.