Question

KOH + CH3-C(CH3)2CH2Br
The reactants in the reaction will undergo

a)nucleophilic substitution reactions
b)elimination reaction
c)nucleophilic addition reactions

Answer 1

Answer: a. Nucleophilic Substitution Reaction

Explanation: It will undergo through Sn2 Mechanism as the halogen is attached to 1° Carbon. [Reactivity Order of Sn2: Ch₃°>1°>2°>3°]

→It will not undergo through Elimination reaction because in this reaction it is not mentioned that KOH is alcoholic so it means KOH is in aq. state.

→It will not undergo nucleophilic addition reaction beacuse there's no ketone or aldehyde group present in it.

Answer 2

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★ CASE 1

→ If it is alcoholic KOH , then it acts as strong NUCLEOPHILE and ELIMINATION REACTION will takes place.

product formed (after rearrangement )
is

CH3-C(CH3)2=CH2

(Alkyl group is eliminated)

★ CASE 2

→ If it is aqueous KOH

then it acts as weak nucleophile and NSR(NUCLEOPHILIC SUBSTITUTION REACTION ) will takes place

product formed is

CH3- CH(OH)CH3-CH2-CH3

As it is not mentioned in question whether it is aqueous or Alcoholic koh
(we assume it as aqueous)

so, answer is option (1)NUCLEOPHILIC SUBSTITUTION REACTION

happy to help!!

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