Math, asked by soumiyapal, 19 days ago

koi 36th questions ke answer dedo​

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Answered by diwanamrmznu
8

★Given:-

 \implies \red{15x + 12y = 27} \\

★find:-

three solution given EQ and draw it's graph

 \implies \red{15x + 12y = 27} \\

transposition

 \implies \orange{12y  = 27 - 15x} \\  \\  \\ \implies  \star\pink{y  =  \frac{27 - 15x}{12} }

when x=0

 \implies \: y =  \frac{27 - 15(0)}{12} \\  \\  \\   \implies \: y =  \frac{27 - 0}{12}   \\  \\  \\  \implies \:  y = \frac{27}{12}  \\  \\  \\  \implies \: y = 2.25

A=cordinate (x,y)=(0, 2.25)

when x=1

  •  \implies \: y =  \frac{27 - 15(1)}{12}  \\  \\  \\   \implies \: y =  \frac{27 - 15}{12}  \\  \\  \\  \implies \: y =  \frac{12}{12}   \\  \\  \\  \implies \: y = 1

B=cordinate (x,y)=(1,1)

when x=5

 \implies \: y =  \frac{27 - 15(5)}{12}  \\  \\  \\  \implies \: y =  \frac{27 - 75}{12}  \\  \\  \\  \implies \: y =  \frac{ - 48}{ \:  \:  \:  \: 12}  \\  \\  \\  \implies \: y =  - 4

C=cordinate (x,y)=(5,-4)

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I hope it helps you

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