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1
here,,It is given that
temperature is favourable to this reaction..
so,
heat of product will be higher then that of reactant....
This means that the reaction is exothermic..
so,
this means,heat formed in product-heat in reactant will be greater than zero
so,∆H will be positive
In that case.... ∆H will also,be positive
option1) is the correct one......
{hope it helps}
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0
Answer:
(2) I sure
Explanation:
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