Question

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Q1.Two point charges 4Q, Q are separated by lm in air. At what point on the line joining the charges is the electric field intensity zero?
Also calculate the electrostatic potential energy of the system of charges, taking the value of charge, Q = 2 ×10^-7C.​

Answer 1

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Let, the required point be P, at a distance x from charge 4Q and, at (1-x) distance from charge Q. Therefore, electric field intensity is 0 at x= 2 3 m from charge 4Q. (ii) Electrostatic potential energy of the system is given as, Therefore, electrostatic potential energy of the ststem of charges is equal to 1 .

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