koi hai ?__A ball is thrown vertically upwards 40 metres per second : calculate the greatest height attained and its velocity after 3 seconds
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Given Initial velocity of ball, u = 49 m/s Let the maximum height reached and time taken to reach that height be H and t respectively.
Assumption: g = 9.8 m/s² holds true (maximum height reached is small compared to the radius of earth)
Velocity of the ball at maximum height is zero, v = 0
v² u² = 2aH 0 (49)² = 2 × (-9.8) × H H 122.5 m
v = u + at
0499.8t ⇒ t 5s
..Total time taken by ball to return to the surface, T = 2t = 10 s
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