Question

koi help kardo na.

A rectangle is 16 m by 9 m. Find a side of the square whose area equals the area of the rectangle. By how much does the perimeter of the rectangle exceed the perimeter of the square?


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Answer 1

Answer:

side of the square is

Root [16 X 9]

root 144

12m

Explanation:

perimeter of the rectangle is

2[l + b]

2[ 16 + 9 ]

2 X 25

50m

the perimeter of the square is

4 times side

4 X 12

48m

difference is

50-48

2m

Answer 2

Answer:

Area of rectangle =(16×9)m

2

=144m

2

Given condition,

Area of square = Area of rectangle

⇒(side)

2

=144

∴side=

144

=12m

Now,

Perimeter of square =4×side=4×12=48m

Perimeter of rectangle =2(l+b)=2(16+9)=50m

Hence, difference in their perimeters =50−48=2m