Question

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mera 1 HR
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Answer 1

Given :

• Height of Conical Tent is 8 m .
• Radius of Tent is 6 m .

To Find :

• Length of trapaulin required to make the conical tent .

Solution :

Firstly we will find Slant Height :

$\longmapsto\tt{l=\sqrt{{(h)}^{2}+{(r)}^{2}}}$

$\longmapsto\tt{l=\sqrt{{(8)}^{2}+{(6)}^{2}}}$

$\longmapsto\tt{l=\sqrt{64+36}}$

$\longmapsto\tt{l=\sqrt{100}}$

$\longmapsto\tt\bf{l=10\:cm}$

Now ,

For Area of Canvas :

Using Formula :

$\longmapsto\tt\boxed{C.S.A\:of\:Cone=\pi{rl}}$

Putting Values :

$\longmapsto\tt{\dfrac{314}{10{\not{0}}}\times{6}\times{1{\not{0}}}}$

$\longmapsto\tt{\dfrac{942}{5}}$

$\longmapsto\tt\bf{188.4\:{m}^{2}}$

Now ,

$\longmapsto\tt{Length\:of\:Trapaulin=\dfrac{Area}{Width}}$

$\longmapsto\tt{\dfrac{1884}{3\times{10}}}$

$\longmapsto\tt{\dfrac{628}{10}}$

$\longmapsto\tt\bf{62.8\:m}$

Extra Material Required :

$\longmapsto\tt{\dfrac{20}{100}}$

$\longmapsto\tt{0.2\:m}$

Total Length Required :

$\longmapsto\tt{62.8+0.2}$

$\longmapsto\tt\bf{63\:m}$

Answer 2

Answer:

Height of conical tent, h = 8m

Radius of base of tent, r = 6m

Slant height of tent, l2 = (r2+h2)

l2 = (62+82) = (36+64) = (100)

or l = 10

Again, CSA of conical tent = πrl

= (3.14×6×10) m2

= 188.4m2

Let the length of tarpaulin sheet required be L

As 20 cm will be wasted, therefore,

Effective length will be (L-0.2m).

Breadth of tarpaulin = 3m (given)

Area of sheet = CSA of tent

[(L–0.2)×3] = 188.4

L-0.2 = 62.8

L = 63

Therefore, the length of the required tarpaulin sheet will be 63 m.

Step-by-step explanation:

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