Question

koi moderator please help me find this​

Answer 1

Given

lenght = 15 + 2x

width = x

area = 320m²

Area of rectangle = length × width

• (15 + 2x) × x = 320
• 15x + 2x²= 320

$\red{\boxed{2x²\:+ \:15x \:- \:320 \:= \:0\:}}$

is the required equation.

Now solving for "x" in the equation.

• 2x²+ 15x - 320 = 0

Discriminant

D= b²-4ac

D = 225 +2560

D = 2785

= distinct roots

using quadratic formula:-

attachment

$x = \frac{ - 15 + - \sqrt{2560} }{4}$

• Hope it helps you
• thanks
• regards, AKASHITEMHEAVEN

Answer 2

Answer:

Given

lenght = 15 + 2x

width = x

area = 320m²

Area of rectangle = length × width

(15 + 2x) × x = 320

15x + 2x²= 320

\red{\boxed{2x²\:+ \:15x \:- \:320 \:= \:0\:}}2x²+15x−320=0

is the required equation.

Now solving for "x" in the equation.

2x²+ 15x - 320 = 0

Discriminant

D= b²-4ac

D = 225 +2560

D = 2785

= distinct roots

using quadratic formula:-

attachment

x = \frac{ - 15 + - \sqrt{2560} }{4}x=4−15+−2560