Question

Koi question ka solution dedo,
Kab se try nahi bana,
samajh ke bahar hai
answer the 12 th​

Answer 1

Applying shree dhar Aacharya formula

$\LARGE \rightarrow x^2+6√6+48$

$\LARGE x=\frac{-b±\sqrt{b^2-4ac}}{2a}$

$\LARGE x=\frac{-6√6±\sqrt{6√6^2-4(48)(1)}}{2(1)}$

$\LARGE x=\frac{-6√6±\sqrt{24}}{2}$

$\LARGE x=-3√6±√6$

$\LARGE x= -2√6 and -4√6$

NOW THE EQUATION CAN BE WRITTEN AS

$\LARGE (X+2√6)(X+4√6)$