Question

koi solution btao 9 and 10 please please please please please.... test hai...​

Answer 1

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$\huge\bold\red{Answer}$

Value Of k = -2/3

Explanation:

Compare given Quadratic polynomial (kx²+2x+3k) by ax²+bx+c, we get

we geta = k , b = 2 , c = 3k

$sum \: of \: the \: zeroes \: = \frac{ - b}{a} \\ = \frac{ - 2}{k} .......(i) \\ \\ product \: of \: zeroes = \frac{c}{a} \\ = \frac{3k}{k} \\ = 3..........(ii)$

According to question,

$\frac{ - 2}{k} = 3 \\ - 2 = 3k \\ k = \frac{ - 2}{3}$

Hence, value of k is -2/3.

Question.2, Refer to this attachment...

I Hope It Helps You✌️

Answer 2

Answer:

9.

$k = \frac{ - 2}{ \: \: 3 }$

10. Remainder = -31. ( verification in the attachment)

Step-by-step explanation:

Refer to the attachment...