Math, asked by ashmitsingh718p6ehon, 1 year ago

Koi solve karoo Physics waalon se nhi huaa

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Answered by Raunakc
0

Answer:

4Ω

Step-by-step explanation:

R¹ = 3Ω

R² = 6Ω

R³ = 2Ω

V = 24 V

I¹= 2A

I² = 1A

I = 2+1 = 3A

V= IR

24 /3 = R

R = 8Ω

1/R( p) = 1/R¹ + 1/R²

= 1/3 + 1/6

=3/6

=1/2

R(p) = 2Ω

R(s) = R(p) + R³

= 2+2

= 4Ω

Total Resistance = R + R of battery

8- 4 = R of battery

R of bAterry = 4Ω

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